-2[-2(y+1)-3(y-2)]=8

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Solution for -2[-2(y+1)-3(y-2)]=8 equation:


Simplifying
-2[-2(y + 1) + -3(y + -2)] = 8

Reorder the terms:
-2[-2(1 + y) + -3(y + -2)] = 8
-2[(1 * -2 + y * -2) + -3(y + -2)] = 8
-2[(-2 + -2y) + -3(y + -2)] = 8

Reorder the terms:
-2[-2 + -2y + -3(-2 + y)] = 8
-2[-2 + -2y + (-2 * -3 + y * -3)] = 8
-2[-2 + -2y + (6 + -3y)] = 8

Reorder the terms:
-2[-2 + 6 + -2y + -3y] = 8

Combine like terms: -2 + 6 = 4
-2[4 + -2y + -3y] = 8

Combine like terms: -2y + -3y = -5y
-2[4 + -5y] = 8
[4 * -2 + -5y * -2] = 8
[-8 + 10y] = 8

Solving
-8 + 10y = 8

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 10y = 8 + 8

Combine like terms: -8 + 8 = 0
0 + 10y = 8 + 8
10y = 8 + 8

Combine like terms: 8 + 8 = 16
10y = 16

Divide each side by '10'.
y = 1.6

Simplifying
y = 1.6

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